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STRAIGHT LINE
Straight line is the locus of a moving point P (h, k), which moves in such a condition that P is always collinear with the given two fixed points. Also, we know from the concept of collinearity that, three points are collinear if they lie on a same straight line or the area of triangle from by these points is zero. CENTROID, INCENTRE AND CRICUMCENTRE Key Points: In a right angled triangle, orthocentre is the point where right angle is formed. In an isosceles triangle, all of centroid, orthocentre, incentre and circumcentre lie on the same line. REVISION NOTES FOR SCIENCE CHAPTER 3 Get Revision notes of Class 8th Science Chapter 3 Synthetic fibres and plastics to score good marks in your Exams. Our notes of Chapter 3 Synthetic fibres and plastics are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads, NCERT & other Competitive Exams. PHYSICAL CHEMISTRY- REVISION NOTES ON GASEOUS STATE FOR Equation for combustion of hydrocarbons: C x H y + (x + y/4) O 2 ——> xCO 2 + y/2 H 2 O. Kinetic molecular theory of gases: Gases are made of large number of identical particles (atoms or molecules), which are very small and perfectly hard spheres. THE CURRENT OF 13.4A IS PASSED THROUGH 1 L OF 1.0M HCL The current of 13.4A is passed through 1 L of 1.0M HCl solution for 1hr .the pH of the solution after the experiment is over will be about ? at cathode :- hydr A=2I+PJ+QK AND B=5I+7J+3K.IF VECTOR A PARALLEL VECTOR B A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the valu - askIITians. sakshi singh Grade: 11. A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the values of p and q are,respectively a)
CONSIDER A VECTOR F=4I-3J. ANOTHER VECTOR THAT ISTHE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J0K CAP IS ANSWER OF THE ABOVERY QUESTION. IT WILL BE A UNIT VECTOR ALONG Z -AXIS AS F VECTOR LIES IN X-Y PLANE.0CONSIDER A VECTOR F =4ICAP-3JCAP.THE VECTOR PERPENDICULAR TO VECTOR F IS??WHAT IS THE UNIT VECTOR OF F0THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE XI+YJ (4I-3J) . (XI+YJ)=0 4X-3Y=0 4X=3Y P=3I +4J I J K 3 4 0 4 -3 0 BY USING CROSS PRODUCT...0IN CARTESIAN FORM OF VECTORS ,ALL VECTORS ARE PERPENDICULAR TO EACH OTHER . WE HAVE GIVEN, F=4I-3J ACCORDING TO CARTESIAN FORM,K WILL BE PERPENDICU...0THE ANS IS 7K CAP. I KNOW PHY IS TOUGH BUT REGULAR PRACTICE WILL MAKE IT EASY THE MORE QUESTION U SOLVE MORE KNOWLEDGE U WILL GET0HELLO STUDENT THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J HOPE IT HELPS...0PLEASE REFER HTTPS://WWW.ASKIITIANS.COM/FORUMS/MECHANICS/CONSIDER-A-VECTOR-F-4I-3J-ANOTHER-VECTOR-THAT-IS_137170.HTM0 8 Answers. K cap is answer of the abovery question. It will be a unit vector along z -axis as F vector lies in X-Y plane. (4i-3j) . (Xi+yj)=0. in cartesian form of vectors ,all vectors are perpendicularto each other .
THE FORCE BETWEEN TWO BAR MAGNETS WHOSE CENTERS ARE D The force between two bar magnets whose centers are d metres apart is 4.8N. When the separation is made 2d the force is reduced to (a) 2.4 N (b) 1.2 N (c) 0.6 N (d) 0.3 N. We will notify on your mail & mobile when someone answers this question. ONLINE COACHING FOR IIT JEE, MEDICAL & SCHOOL ENTRANCETWO YEARS PROGRAMONE YEAR PROGRAMLIVE ONLINE CLASSESTEST SERIESONE TO ONE Crack IIT JEE & other engineering & school exams through askIITians online coaching, free study material, books & past papers for Indians as well as NRI students. Click here for a free demo class. CBSE CLASS 12 PHYSICS PRACTICAL SYLLABUS 2021-2022, ONLINE CBSE Class 12 Physics Practical Syllabus 2021-2022. You must take note of Class 12 Physics practicals syllabus so that you can achieve full marks in the practical examination. Many students focus majorly on the CBSE Class 12 Physics theory paper.STRAIGHT LINE
Straight line is the locus of a moving point P (h, k), which moves in such a condition that P is always collinear with the given two fixed points. Also, we know from the concept of collinearity that, three points are collinear if they lie on a same straight line or the area of triangle from by these points is zero. CENTROID, INCENTRE AND CRICUMCENTRE Key Points: In a right angled triangle, orthocentre is the point where right angle is formed. In an isosceles triangle, all of centroid, orthocentre, incentre and circumcentre lie on the same line. BIOLOGY - BIOLOGICAL CLASSIFICATION REVISION NOTES FOR Revision Notes on Biological Classification Systems of Classification:. Identification of differences among organisms and placing them into groups that reflect their most significant features and relationship is called biological classification.. Biological classification was first proposed by Aristotle who divided plants into herbs, shrubs and trees.BIOLOGY – CELL
Revision Notes on Cell-The Unit of Life (1) Cytology: (G.k. kyios = cell ; logas = study) is the branch of biology which comprises the study of cell structure and function. (2) Cell is the structural and functional unit of all living beings. (3) There are two types of cells: plant cell and animal cell. THE CURRENT OF 13.4A IS PASSED THROUGH 1 L OF 1.0M HCL The current of 13.4A is passed through 1 L of 1.0M HCl solution for 1hr .the pH of the solution after the experiment is over will be about ? at cathode :- hydr CONSIDER A VECTOR F=4I-3J. ANOTHER VECTOR THAT ISTHE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J0K CAP IS ANSWER OF THE ABOVERY QUESTION. IT WILL BE A UNIT VECTOR ALONG Z -AXIS AS F VECTOR LIES IN X-Y PLANE.0CONSIDER A VECTOR F =4ICAP-3JCAP.THE VECTOR PERPENDICULAR TO VECTOR F IS??WHAT IS THE UNIT VECTOR OF F0THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE XI+YJ (4I-3J) . (XI+YJ)=0 4X-3Y=0 4X=3Y P=3I +4J I J K 3 4 0 4 -3 0 BY USING CROSS PRODUCT...0IN CARTESIAN FORM OF VECTORS ,ALL VECTORS ARE PERPENDICULAR TO EACH OTHER . WE HAVE GIVEN, F=4I-3J ACCORDING TO CARTESIAN FORM,K WILL BE PERPENDICU...0THE ANS IS 7K CAP. I KNOW PHY IS TOUGH BUT REGULAR PRACTICE WILL MAKE IT EASY THE MORE QUESTION U SOLVE MORE KNOWLEDGE U WILL GET0HELLO STUDENT THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J HOPE IT HELPS...0PLEASE REFER HTTPS://WWW.ASKIITIANS.COM/FORUMS/MECHANICS/CONSIDER-A-VECTOR-F-4I-3J-ANOTHER-VECTOR-THAT-IS_137170.HTM0 8 Answers. K cap is answer of the abovery question. It will be a unit vector along z -axis as F vector lies in X-Y plane. (4i-3j) . (Xi+yj)=0. in cartesian form of vectors ,all vectors are perpendicularto each other .
THE MOLECULE, AB OF A COMPOUND FORMS CUBIC LATTICE WHERE The molecule, AB of a compound forms cubic lattice where ‘A’ atoms occupy the corners and B atoms occupy the alternate faces of the unit cell. The formula of the compound is. (a) A2B (b) AB2 (c) AB (d) A2B2 ? We will notify on your mail & mobile when someone answers thisquestion.
LOG 18 TO THE BASE 4 IS (1) RATIONAL NUMBER (2) AN 2 years ago. Dear Ananya. Log 18 to the base 4 is irrational number. as. let it is a rational number. log 4 18 = p/q. 4^ (p/q) = 18. 2^ (2p/q) = 18. it is never possible hence it is an irrational number. TIPS TO CRACK IIT JEE ADVANCED IN 1 YEAR Eat healthy because you need tremendous energy to sustain the preparation for a year. Drink lots of water as it is a necessity. Exercise or meditate so that your body and mind are in sync and you get the desired strength from within. You can follow these tips to crack IIT JEE in 1 year and nothing can come your way from fulfillingyour dream.
REVISION NOTES FOR SCIENCE CHAPTER 3 Get Revision notes of Class 8th Science Chapter 3 Synthetic fibres and plastics to score good marks in your Exams. Our notes of Chapter 3 Synthetic fibres and plastics are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads, NCERT & other Competitive Exams. PHYSICAL CHEMISTRY- REVISION NOTES ON SOME BASIC CONCEPTS Elements: It is the simplest form of the matter. Smallest unit of an element is known as atom. Total number of the known elements is 118 out of which 98 elements occur naturally and 20 are formed by artificial transmutation. R.D. SHARMA CLASS 8 SOLUTIONS R.D. Sharma Class 8 Complete Solutions: askIITians provide complete solutions for chapter 1 to 27 with solved examples. Solutions are prepared by IITians as per NCERT guidelines. HOW TO PREPARE YOURSELF FOR 11TH GRADE How to Prepare Yourself for 11 th Grade?. Students usually take a back step from studies once they are through with Class 10 th. After all of the pressure of the much hyped board exams of class 10 th and on the way to the 12 th boards, 11 th grade may seem like a welcome change for you. But the difficulty level of class 11 th will dawn upon you sooner or later. 11 th is very different in terms REVISION NOTES FOR SCIENCE CHAPTER 2 Get Revision notes of Class 9 th Science Chapter 2 Is Matter around us pure to score good marks in your Exams. Our notes of Chapter 2 Is Matter around us pure are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads,NCERT &
CHOOSING BETWEEN MBA AND M. TECH AFTER B. TECH Prospects for MBA and M. Tech Professionals. The first choice of stream in MBA for a B. Tech candidate should be Operations, as technical know-how and operational work go well hand in hand. Secondly, they can opt for MBA in Finance or IB, and then followed by MBA in Sales and Marketing. There is no point choosing an MBA in HRafter a B. Tech.
WHAT IS THE FUNCTION OF DRY AND MOIST AG2O IN ALKYL HALIDE 2 Answers. we can consider moist Ag2O as AgOH, which reacts with RX following SN2 mechanism. while dry Ag2O yields ethers, also following SN2 mechanism. Ag2O catalyses the removal of halide ion as AgX. The RO- then acts as a strong enough nucleophile to affect the SN2 mechanism. Moist Ag2Oreleases OH- in low concentration as AgOH is aweak base.
A HORSE PULLS A CART WITH A FORCE OF 42.0 LB AT AN ANGLE A horse pulls a cart with a force of 42.0 lb at an angle of 27.0° with the horizontal and moves along at a speed of6.20 mi/h. (a) How much work does the horse do in 12.0 min? (b) Find the power output of the horse, in hp of course. A horse pulls a cart with a force of 42.0 lb at an angle of 27.0° with the horizontal and moves along at aspeed
WHAT IS THE MASS PERCENT OF FE3+ IONS IN FE0.93O1.00(THE What is the mass percent of Fe3+ ions in Fe0.93O1.00(the numbers 0.93 and 1.00 are subscripts). please help Dear Student , let out of 0.93,Fe 3+ =x and Fe 2+
ONLINE COACHING FOR IIT JEE, MEDICAL & SCHOOL ENTRANCETWO YEARS PROGRAMONE YEAR PROGRAMLIVE ONLINE CLASSESTEST SERIESONE TO ONE Crack IIT JEE & other engineering & school exams through askIITians online coaching, free study material, books & past papers for Indians as well as NRI students. Click here for a free demo class. BIOLOGY - BIOLOGICAL CLASSIFICATION REVISION NOTES FOR Revision Notes on Biological Classification Systems of Classification:. Identification of differences among organisms and placing them into groups that reflect their most significant features and relationship is called biological classification.. Biological classification was first proposed by Aristotle who divided plants into herbs, shrubs and trees.STRAIGHT LINE
Straight line is the locus of a moving point P (h, k), which moves in such a condition that P is always collinear with the given two fixed points. Also, we know from the concept of collinearity that, three points are collinear if they lie on a same straight line or the area of triangle from by these points is zero. CENTROID, INCENTRE AND CRICUMCENTRE Key Points: In a right angled triangle, orthocentre is the point where right angle is formed. In an isosceles triangle, all of centroid, orthocentre, incentre and circumcentre lie on the same line. REVISION NOTES FOR SCIENCE CHAPTER 3 Get Revision notes of Class 8th Science Chapter 3 Synthetic fibres and plastics to score good marks in your Exams. Our notes of Chapter 3 Synthetic fibres and plastics are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads, NCERT & other Competitive Exams. PHYSICAL CHEMISTRY- REVISION NOTES ON GASEOUS STATE FOR Equation for combustion of hydrocarbons: C x H y + (x + y/4) O 2 ——> xCO 2 + y/2 H 2 O. Kinetic molecular theory of gases: Gases are made of large number of identical particles (atoms or molecules), which are very small and perfectly hard spheres. THE CURRENT OF 13.4A IS PASSED THROUGH 1 L OF 1.0M HCL The current of 13.4A is passed through 1 L of 1.0M HCl solution for 1hr .the pH of the solution after the experiment is over will be about ? at cathode :- hydr A=2I+PJ+QK AND B=5I+7J+3K.IF VECTOR A PARALLEL VECTOR B A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the valu - askIITians. sakshi singh Grade: 11. A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the values of p and q are,respectively a)
CONSIDER A VECTOR F=4I-3J. ANOTHER VECTOR THAT ISTHE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J0K CAP IS ANSWER OF THE ABOVERY QUESTION. IT WILL BE A UNIT VECTOR ALONG Z -AXIS AS F VECTOR LIES IN X-Y PLANE.0CONSIDER A VECTOR F =4ICAP-3JCAP.THE VECTOR PERPENDICULAR TO VECTOR F IS??WHAT IS THE UNIT VECTOR OF F0THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE XI+YJ (4I-3J) . (XI+YJ)=0 4X-3Y=0 4X=3Y P=3I +4J I J K 3 4 0 4 -3 0 BY USING CROSS PRODUCT...0IN CARTESIAN FORM OF VECTORS ,ALL VECTORS ARE PERPENDICULAR TO EACH OTHER . WE HAVE GIVEN, F=4I-3J ACCORDING TO CARTESIAN FORM,K WILL BE PERPENDICU...0THE ANS IS 7K CAP. I KNOW PHY IS TOUGH BUT REGULAR PRACTICE WILL MAKE IT EASY THE MORE QUESTION U SOLVE MORE KNOWLEDGE U WILL GET0HELLO STUDENT THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J HOPE IT HELPS...0PLEASE REFER HTTPS://WWW.ASKIITIANS.COM/FORUMS/MECHANICS/CONSIDER-A-VECTOR-F-4I-3J-ANOTHER-VECTOR-THAT-IS_137170.HTM0 8 Answers. K cap is answer of the abovery question. It will be a unit vector along z -axis as F vector lies in X-Y plane. (4i-3j) . (Xi+yj)=0. in cartesian form of vectors ,all vectors are perpendicularto each other .
THE FORCE BETWEEN TWO BAR MAGNETS WHOSE CENTERS ARE D The force between two bar magnets whose centers are d metres apart is 4.8N. When the separation is made 2d the force is reduced to (a) 2.4 N (b) 1.2 N (c) 0.6 N (d) 0.3 N. We will notify on your mail & mobile when someone answers this question. ONLINE COACHING FOR IIT JEE, MEDICAL & SCHOOL ENTRANCETWO YEARS PROGRAMONE YEAR PROGRAMLIVE ONLINE CLASSESTEST SERIESONE TO ONE Crack IIT JEE & other engineering & school exams through askIITians online coaching, free study material, books & past papers for Indians as well as NRI students. Click here for a free demo class. BIOLOGY - BIOLOGICAL CLASSIFICATION REVISION NOTES FOR Revision Notes on Biological Classification Systems of Classification:. Identification of differences among organisms and placing them into groups that reflect their most significant features and relationship is called biological classification.. Biological classification was first proposed by Aristotle who divided plants into herbs, shrubs and trees.STRAIGHT LINE
Straight line is the locus of a moving point P (h, k), which moves in such a condition that P is always collinear with the given two fixed points. Also, we know from the concept of collinearity that, three points are collinear if they lie on a same straight line or the area of triangle from by these points is zero. CENTROID, INCENTRE AND CRICUMCENTRE Key Points: In a right angled triangle, orthocentre is the point where right angle is formed. In an isosceles triangle, all of centroid, orthocentre, incentre and circumcentre lie on the same line. REVISION NOTES FOR SCIENCE CHAPTER 3 Get Revision notes of Class 8th Science Chapter 3 Synthetic fibres and plastics to score good marks in your Exams. Our notes of Chapter 3 Synthetic fibres and plastics are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads, NCERT & other Competitive Exams. PHYSICAL CHEMISTRY- REVISION NOTES ON GASEOUS STATE FOR Equation for combustion of hydrocarbons: C x H y + (x + y/4) O 2 ——> xCO 2 + y/2 H 2 O. Kinetic molecular theory of gases: Gases are made of large number of identical particles (atoms or molecules), which are very small and perfectly hard spheres. THE CURRENT OF 13.4A IS PASSED THROUGH 1 L OF 1.0M HCL The current of 13.4A is passed through 1 L of 1.0M HCl solution for 1hr .the pH of the solution after the experiment is over will be about ? at cathode :- hydr A=2I+PJ+QK AND B=5I+7J+3K.IF VECTOR A PARALLEL VECTOR B A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the valu - askIITians. sakshi singh Grade: 11. A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the values of p and q are,respectively a)
CONSIDER A VECTOR F=4I-3J. ANOTHER VECTOR THAT ISTHE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J0K CAP IS ANSWER OF THE ABOVERY QUESTION. IT WILL BE A UNIT VECTOR ALONG Z -AXIS AS F VECTOR LIES IN X-Y PLANE.0CONSIDER A VECTOR F =4ICAP-3JCAP.THE VECTOR PERPENDICULAR TO VECTOR F IS??WHAT IS THE UNIT VECTOR OF F0THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE XI+YJ (4I-3J) . (XI+YJ)=0 4X-3Y=0 4X=3Y P=3I +4J I J K 3 4 0 4 -3 0 BY USING CROSS PRODUCT...0IN CARTESIAN FORM OF VECTORS ,ALL VECTORS ARE PERPENDICULAR TO EACH OTHER . WE HAVE GIVEN, F=4I-3J ACCORDING TO CARTESIAN FORM,K WILL BE PERPENDICU...0THE ANS IS 7K CAP. I KNOW PHY IS TOUGH BUT REGULAR PRACTICE WILL MAKE IT EASY THE MORE QUESTION U SOLVE MORE KNOWLEDGE U WILL GET0HELLO STUDENT THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J HOPE IT HELPS...0PLEASE REFER HTTPS://WWW.ASKIITIANS.COM/FORUMS/MECHANICS/CONSIDER-A-VECTOR-F-4I-3J-ANOTHER-VECTOR-THAT-IS_137170.HTM0 8 Answers. K cap is answer of the abovery question. It will be a unit vector along z -axis as F vector lies in X-Y plane. (4i-3j) . (Xi+yj)=0. in cartesian form of vectors ,all vectors are perpendicularto each other .
THE FORCE BETWEEN TWO BAR MAGNETS WHOSE CENTERS ARE D The force between two bar magnets whose centers are d metres apart is 4.8N. When the separation is made 2d the force is reduced to (a) 2.4 N (b) 1.2 N (c) 0.6 N (d) 0.3 N. We will notify on your mail & mobile when someone answers this question. TIPS TO CRACK IIT JEE ADVANCED IN 1 YEAR Eat healthy because you need tremendous energy to sustain the preparation for a year. Drink lots of water as it is a necessity. Exercise or meditate so that your body and mind are in sync and you get the desired strength from within. You can follow these tips to crack IIT JEE in 1 year and nothing can come your way from fulfillingyour dream.
REVISION NOTES FOR SCIENCE CHAPTER 3 Get Revision notes of Class 8th Science Chapter 3 Synthetic fibres and plastics to score good marks in your Exams. Our notes of Chapter 3 Synthetic fibres and plastics are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads, NCERT & other Competitive Exams. PHYSICAL CHEMISTRY- REVISION NOTES ON SOME BASIC CONCEPTS Elements: It is the simplest form of the matter. Smallest unit of an element is known as atom. Total number of the known elements is 118 out of which 98 elements occur naturally and 20 are formed by artificial transmutation. R.D. SHARMA CLASS 8 SOLUTIONS R.D. Sharma Class 8 Complete Solutions: askIITians provide complete solutions for chapter 1 to 27 with solved examples. Solutions are prepared by IITians as per NCERT guidelines. HOW TO PREPARE YOURSELF FOR 11TH GRADE How to Prepare Yourself for 11 th Grade?. Students usually take a back step from studies once they are through with Class 10 th. After all of the pressure of the much hyped board exams of class 10 th and on the way to the 12 th boards, 11 th grade may seem like a welcome change for you. But the difficulty level of class 11 th will dawn upon you sooner or later. 11 th is very different in terms REVISION NOTES FOR SCIENCE CHAPTER 2 Get Revision notes of Class 9 th Science Chapter 2 Is Matter around us pure to score good marks in your Exams. Our notes of Chapter 2 Is Matter around us pure are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads,NCERT &
CHOOSING BETWEEN MBA AND M. TECH AFTER B. TECH Prospects for MBA and M. Tech Professionals. The first choice of stream in MBA for a B. Tech candidate should be Operations, as technical know-how and operational work go well hand in hand. Secondly, they can opt for MBA in Finance or IB, and then followed by MBA in Sales and Marketing. There is no point choosing an MBA in HRafter a B. Tech.
WHAT IS THE FUNCTION OF DRY AND MOIST AG2O IN ALKYL HALIDE 2 Answers. we can consider moist Ag2O as AgOH, which reacts with RX following SN2 mechanism. while dry Ag2O yields ethers, also following SN2 mechanism. Ag2O catalyses the removal of halide ion as AgX. The RO- then acts as a strong enough nucleophile to affect the SN2 mechanism. Moist Ag2Oreleases OH- in low concentration as AgOH is aweak base.
A HORSE PULLS A CART WITH A FORCE OF 42.0 LB AT AN ANGLE A horse pulls a cart with a force of 42.0 lb at an angle of 27.0° with the horizontal and moves along at a speed of6.20 mi/h. (a) How much work does the horse do in 12.0 min? (b) Find the power output of the horse, in hp of course. A horse pulls a cart with a force of 42.0 lb at an angle of 27.0° with the horizontal and moves along at aspeed
WHAT IS THE MASS PERCENT OF FE3+ IONS IN FE0.93O1.00(THE What is the mass percent of Fe3+ ions in Fe0.93O1.00(the numbers 0.93 and 1.00 are subscripts). please help Dear Student , let out of 0.93,Fe 3+ =x and Fe 2+
ONLINE COACHING FOR IIT JEE, MEDICAL & SCHOOL ENTRANCETWO YEARS PROGRAMONE YEAR PROGRAMLIVE ONLINE CLASSESTEST SERIESONE TO ONE Crack IIT JEE & other engineering & school exams through askIITians online coaching, free study material, books & past papers for Indians as well as NRI students. Click here for a free demo class. BIOLOGY - BIOLOGICAL CLASSIFICATION REVISION NOTES FOR Revision Notes on Biological Classification Systems of Classification:. Identification of differences among organisms and placing them into groups that reflect their most significant features and relationship is called biological classification.. Biological classification was first proposed by Aristotle who divided plants into herbs, shrubs and trees.STRAIGHT LINE
Straight line is the locus of a moving point P (h, k), which moves in such a condition that P is always collinear with the given two fixed points. Also, we know from the concept of collinearity that, three points are collinear if they lie on a same straight line or the area of triangle from by these points is zero. CENTROID, INCENTRE AND CRICUMCENTRE Key Points: In a right angled triangle, orthocentre is the point where right angle is formed. In an isosceles triangle, all of centroid, orthocentre, incentre and circumcentre lie on the same line. REVISION NOTES FOR SCIENCE CHAPTER 3 Get Revision notes of Class 8th Science Chapter 3 Synthetic fibres and plastics to score good marks in your Exams. Our notes of Chapter 3 Synthetic fibres and plastics are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads, NCERT & other Competitive Exams. PHYSICAL CHEMISTRY- REVISION NOTES ON GASEOUS STATE FOR Equation for combustion of hydrocarbons: C x H y + (x + y/4) O 2 ——> xCO 2 + y/2 H 2 O. Kinetic molecular theory of gases: Gases are made of large number of identical particles (atoms or molecules), which are very small and perfectly hard spheres. THE CURRENT OF 13.4A IS PASSED THROUGH 1 L OF 1.0M HCL The current of 13.4A is passed through 1 L of 1.0M HCl solution for 1hr .the pH of the solution after the experiment is over will be about ? at cathode :- hydr A=2I+PJ+QK AND B=5I+7J+3K.IF VECTOR A PARALLEL VECTOR B A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the valu - askIITians. sakshi singh Grade: 11. A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the values of p and q are,respectively a)
CONSIDER A VECTOR F=4I-3J. ANOTHER VECTOR THAT ISTHE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J0K CAP IS ANSWER OF THE ABOVERY QUESTION. IT WILL BE A UNIT VECTOR ALONG Z -AXIS AS F VECTOR LIES IN X-Y PLANE.0CONSIDER A VECTOR F =4ICAP-3JCAP.THE VECTOR PERPENDICULAR TO VECTOR F IS??WHAT IS THE UNIT VECTOR OF F0THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE XI+YJ (4I-3J) . (XI+YJ)=0 4X-3Y=0 4X=3Y P=3I +4J I J K 3 4 0 4 -3 0 BY USING CROSS PRODUCT...0IN CARTESIAN FORM OF VECTORS ,ALL VECTORS ARE PERPENDICULAR TO EACH OTHER . WE HAVE GIVEN, F=4I-3J ACCORDING TO CARTESIAN FORM,K WILL BE PERPENDICU...0THE ANS IS 7K CAP. I KNOW PHY IS TOUGH BUT REGULAR PRACTICE WILL MAKE IT EASY THE MORE QUESTION U SOLVE MORE KNOWLEDGE U WILL GET0HELLO STUDENT THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J HOPE IT HELPS...0PLEASE REFER HTTPS://WWW.ASKIITIANS.COM/FORUMS/MECHANICS/CONSIDER-A-VECTOR-F-4I-3J-ANOTHER-VECTOR-THAT-IS_137170.HTM0 8 Answers. K cap is answer of the abovery question. It will be a unit vector along z -axis as F vector lies in X-Y plane. (4i-3j) . (Xi+yj)=0. in cartesian form of vectors ,all vectors are perpendicularto each other .
THE FORCE BETWEEN TWO BAR MAGNETS WHOSE CENTERS ARE D The force between two bar magnets whose centers are d metres apart is 4.8N. When the separation is made 2d the force is reduced to (a) 2.4 N (b) 1.2 N (c) 0.6 N (d) 0.3 N. We will notify on your mail & mobile when someone answers this question. ONLINE COACHING FOR IIT JEE, MEDICAL & SCHOOL ENTRANCETWO YEARS PROGRAMONE YEAR PROGRAMLIVE ONLINE CLASSESTEST SERIESONE TO ONE Crack IIT JEE & other engineering & school exams through askIITians online coaching, free study material, books & past papers for Indians as well as NRI students. Click here for a free demo class. BIOLOGY - BIOLOGICAL CLASSIFICATION REVISION NOTES FOR Revision Notes on Biological Classification Systems of Classification:. Identification of differences among organisms and placing them into groups that reflect their most significant features and relationship is called biological classification.. Biological classification was first proposed by Aristotle who divided plants into herbs, shrubs and trees.STRAIGHT LINE
Straight line is the locus of a moving point P (h, k), which moves in such a condition that P is always collinear with the given two fixed points. Also, we know from the concept of collinearity that, three points are collinear if they lie on a same straight line or the area of triangle from by these points is zero. CENTROID, INCENTRE AND CRICUMCENTRE Key Points: In a right angled triangle, orthocentre is the point where right angle is formed. In an isosceles triangle, all of centroid, orthocentre, incentre and circumcentre lie on the same line. REVISION NOTES FOR SCIENCE CHAPTER 3 Get Revision notes of Class 8th Science Chapter 3 Synthetic fibres and plastics to score good marks in your Exams. Our notes of Chapter 3 Synthetic fibres and plastics are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads, NCERT & other Competitive Exams. PHYSICAL CHEMISTRY- REVISION NOTES ON GASEOUS STATE FOR Equation for combustion of hydrocarbons: C x H y + (x + y/4) O 2 ——> xCO 2 + y/2 H 2 O. Kinetic molecular theory of gases: Gases are made of large number of identical particles (atoms or molecules), which are very small and perfectly hard spheres. THE CURRENT OF 13.4A IS PASSED THROUGH 1 L OF 1.0M HCL The current of 13.4A is passed through 1 L of 1.0M HCl solution for 1hr .the pH of the solution after the experiment is over will be about ? at cathode :- hydr A=2I+PJ+QK AND B=5I+7J+3K.IF VECTOR A PARALLEL VECTOR B A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the valu - askIITians. sakshi singh Grade: 11. A=2i+pj+qk and B=5i+7j+3k.if vector A parallel vector B,then the values of p and q are,respectively a)
CONSIDER A VECTOR F=4I-3J. ANOTHER VECTOR THAT ISTHE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J0K CAP IS ANSWER OF THE ABOVERY QUESTION. IT WILL BE A UNIT VECTOR ALONG Z -AXIS AS F VECTOR LIES IN X-Y PLANE.0CONSIDER A VECTOR F =4ICAP-3JCAP.THE VECTOR PERPENDICULAR TO VECTOR F IS??WHAT IS THE UNIT VECTOR OF F0THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE XI+YJ (4I-3J) . (XI+YJ)=0 4X-3Y=0 4X=3Y P=3I +4J I J K 3 4 0 4 -3 0 BY USING CROSS PRODUCT...0IN CARTESIAN FORM OF VECTORS ,ALL VECTORS ARE PERPENDICULAR TO EACH OTHER . WE HAVE GIVEN, F=4I-3J ACCORDING TO CARTESIAN FORM,K WILL BE PERPENDICU...0THE ANS IS 7K CAP. I KNOW PHY IS TOUGH BUT REGULAR PRACTICE WILL MAKE IT EASY THE MORE QUESTION U SOLVE MORE KNOWLEDGE U WILL GET0HELLO STUDENT THE DOT PRODUCT MUST BE 0 LET THE PERPENDICULAR FORCE BE P = XI+YJ (XI+YJ).(4I-3J)=0 4X-3Y=0 X=3/4Y P=3/4I+J OR P=3I+4J HOPE IT HELPS...0PLEASE REFER HTTPS://WWW.ASKIITIANS.COM/FORUMS/MECHANICS/CONSIDER-A-VECTOR-F-4I-3J-ANOTHER-VECTOR-THAT-IS_137170.HTM0 8 Answers. K cap is answer of the abovery question. It will be a unit vector along z -axis as F vector lies in X-Y plane. (4i-3j) . (Xi+yj)=0. in cartesian form of vectors ,all vectors are perpendicularto each other .
THE FORCE BETWEEN TWO BAR MAGNETS WHOSE CENTERS ARE D The force between two bar magnets whose centers are d metres apart is 4.8N. When the separation is made 2d the force is reduced to (a) 2.4 N (b) 1.2 N (c) 0.6 N (d) 0.3 N. We will notify on your mail & mobile when someone answers this question. TIPS TO CRACK IIT JEE ADVANCED IN 1 YEAR Eat healthy because you need tremendous energy to sustain the preparation for a year. Drink lots of water as it is a necessity. Exercise or meditate so that your body and mind are in sync and you get the desired strength from within. You can follow these tips to crack IIT JEE in 1 year and nothing can come your way from fulfillingyour dream.
REVISION NOTES FOR SCIENCE CHAPTER 3 Get Revision notes of Class 8th Science Chapter 3 Synthetic fibres and plastics to score good marks in your Exams. Our notes of Chapter 3 Synthetic fibres and plastics are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads, NCERT & other Competitive Exams. PHYSICAL CHEMISTRY- REVISION NOTES ON SOME BASIC CONCEPTS Elements: It is the simplest form of the matter. Smallest unit of an element is known as atom. Total number of the known elements is 118 out of which 98 elements occur naturally and 20 are formed by artificial transmutation. R.D. SHARMA CLASS 8 SOLUTIONS R.D. Sharma Class 8 Complete Solutions: askIITians provide complete solutions for chapter 1 to 27 with solved examples. Solutions are prepared by IITians as per NCERT guidelines. HOW TO PREPARE YOURSELF FOR 11TH GRADE How to Prepare Yourself for 11 th Grade?. Students usually take a back step from studies once they are through with Class 10 th. After all of the pressure of the much hyped board exams of class 10 th and on the way to the 12 th boards, 11 th grade may seem like a welcome change for you. But the difficulty level of class 11 th will dawn upon you sooner or later. 11 th is very different in terms REVISION NOTES FOR SCIENCE CHAPTER 2 Get Revision notes of Class 9 th Science Chapter 2 Is Matter around us pure to score good marks in your Exams. Our notes of Chapter 2 Is Matter around us pure are prepared by Maths experts in an easy to remember format, covering all syllabus of CBSE, KVPY, NTSE, Olympiads,NCERT &
CHOOSING BETWEEN MBA AND M. TECH AFTER B. TECH Prospects for MBA and M. Tech Professionals. The first choice of stream in MBA for a B. Tech candidate should be Operations, as technical know-how and operational work go well hand in hand. Secondly, they can opt for MBA in Finance or IB, and then followed by MBA in Sales and Marketing. There is no point choosing an MBA in HRafter a B. Tech.
WHAT IS THE FUNCTION OF DRY AND MOIST AG2O IN ALKYL HALIDE 2 Answers. we can consider moist Ag2O as AgOH, which reacts with RX following SN2 mechanism. while dry Ag2O yields ethers, also following SN2 mechanism. Ag2O catalyses the removal of halide ion as AgX. The RO- then acts as a strong enough nucleophile to affect the SN2 mechanism. Moist Ag2Oreleases OH- in low concentration as AgOH is aweak base.
A HORSE PULLS A CART WITH A FORCE OF 42.0 LB AT AN ANGLE A horse pulls a cart with a force of 42.0 lb at an angle of 27.0° with the horizontal and moves along at a speed of6.20 mi/h. (a) How much work does the horse do in 12.0 min? (b) Find the power output of the horse, in hp of course. A horse pulls a cart with a force of 42.0 lb at an angle of 27.0° with the horizontal and moves along at aspeed
A SMALL PARTICLE CARRYING A NEGATIVE CHARGE OF 1.6*10^-19 a small particle carrying a negative charge of 1.6*10^-19 c is suspend - askIITians. a small particle carrying a negative charge of 1.6*10^-19 c is suspended in equilibrium between the horizontal metal plates 5 cms apart, having a potential difference of 3000v across them. find the mass of the particle?Please Wait...
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