NCERT SOLUTIONS BOOKS CBSE MODEL TEST PAPERS QUESTION PDFCLASS 11 NOTES CHEMISTRY PHYSICS MATHEMATICSNCERT SOLUTIONS Some of the Model test papers are published by NCERT Board. These model test papers contains 10th class maths model paper, maths model for class 9, cbse model paper class 9 ,class 9 science model paper, 10th model question paper etc. Class 1 Model Test Papers Download in pdf. Class 5 Model Test Papers Download in pdf. ENGLISH CORE SAMPLE PAPER FOR CLASS 12 WITH SOLUTION NCERT 1.1 On the basis of your understanding of the above passage, answer any five of the following questions by choosing the most appropriate options : (a) The first green corridor in India was created in : (i) New Delhi. (ii) Chennai. (iii) Mumbai. (iv) Pune. NOTES FOR CLASS 11 ALL SUBJECTS Chemistry Notes for Class 11 Download in pdf. Maths notes and formulas for class 11 download in pdf. Informatics Practices (IP) Notes for class 11 Download in Pdf. Physics notes class 11 cbse board download in pdf. Biology notes class 11 cbse board download in pdf. Economics Notes for class 11 Download in Pdf. Please send your queries at CBSE CLASS 12 BOARD EXAM ACCOUNTANCY PAPER 2018 2019 2020 Question 4: (Marks 1) Diya, Riya and Tiya were partners sharing profits and losses in the ratio of 2 : 3 : 5. Tiya died on 28 th November, 2019. Her share of profit was taken equally by Diya and Riya. Diya’s share of profit in the new firm will be _________ .

Answer :

ANALYSIS SHOWS THAT NICKEL OXIDE HAS THE FORMULA NI0.98O1 Question 16 Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions? Answer Formula is Ni 0.98 O 1.00. So the ration of Ni : O = 98:100. So if there are 100 atoms of oxygen then 98 atoms of Ni. Let number of

atoms of Ni +2 =

CBSE CLASS 12TH ENGLISH CORE QUESTION PAPER SOLVED LAST 10 Question 6: (Marks 10) Rising prices of essential commodities make life difficult for the common man. You are Nalini / Ranbir. Write an article in 150-200 words describing the causes, possible solutions and how students can help their parents to cope with the problem. OR. QUESTION 5. YOU ARE GIVEN A HAMMER, A BATTERY, A BULB Answer: (a) If the substance can be hammered to convert into sheets then it is metal if it is broken into pieces then it is non-metal. Set up the arrangement using bulb, battery, wire and switch as shown in figure. Place the substance between Point A and B if the bulb starts glowing then the substance is a Metal otherwise it is non-metal GOLD (ATOMIC RADIUS = 0.144 NM) CRYSTALLISES IN A FACE Given that. Radius of atom R= 0.144 nm. For a face–centered unit cell. Edge a = 2√2 R. Plug the values we get. Edge a= 0.144 x 2 x 1,414 nm. Edge a= 0.407 nm. Solution:– The length of a side of the cell = 0.407 nm. Please send your queries to ncerthelp@gmail.com GIVEN THE STANDARD ELECTRODE POTENTIALS, K+/K = ?2.93V Question 2:Given the standard electrode potentials, K + /K = −2.93V, Ag + /Ag = 0.80V, Hg 2+ /Hg = 0.79V Mg 2+ /Mg = −2.37 V, Cr 3+ /Cr = − 0.74V Arrange these metals in their increasing order of reducing power. Answer:Reducing power of metals increase with decrease of reduction potential.Hence the increasing order of reducing power will Ag < Hg < Cr < Mg < K A GROUP 14 ELEMENT IS TO BE CONVERTED INTO N?TYPE Question 1.23: A group 14 element is to be converted into n−type semiconductor by doping it with a suitable impurity. To which group should this impurity belong? NCERT SOLUTIONS BOOKS CBSE MODEL TEST PAPERS QUESTION PDFCLASS 11 NOTES CHEMISTRY PHYSICS MATHEMATICSNCERT SOLUTIONS Some of the Model test papers are published by NCERT Board. These model test papers contains 10th class maths model paper, maths model for class 9, cbse model paper class 9 ,class 9 science model paper, 10th model question paper etc. Class 1 Model Test Papers Download in pdf. Class 5 Model Test Papers Download in pdf. ENGLISH CORE SAMPLE PAPER FOR CLASS 12 WITH SOLUTION NCERT 1.1 On the basis of your understanding of the above passage, answer any five of the following questions by choosing the most appropriate options : (a) The first green corridor in India was created in : (i) New Delhi. (ii) Chennai. (iii) Mumbai. (iv) Pune. NOTES FOR CLASS 11 ALL SUBJECTS Chemistry Notes for Class 11 Download in pdf. Maths notes and formulas for class 11 download in pdf. Informatics Practices (IP) Notes for class 11 Download in Pdf. Physics notes class 11 cbse board download in pdf. Biology notes class 11 cbse board download in pdf. Economics Notes for class 11 Download in Pdf. Please send your queries at CBSE CLASS 12 BOARD EXAM ACCOUNTANCY PAPER 2018 2019 2020 Question 4: (Marks 1) Diya, Riya and Tiya were partners sharing profits and losses in the ratio of 2 : 3 : 5. Tiya died on 28 th November, 2019. Her share of profit was taken equally by Diya and Riya. Diya’s share of profit in the new firm will be _________ .

Answer :

ANALYSIS SHOWS THAT NICKEL OXIDE HAS THE FORMULA NI0.98O1 Question 16 Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions? Answer Formula is Ni 0.98 O 1.00. So the ration of Ni : O = 98:100. So if there are 100 atoms of oxygen then 98 atoms of Ni. Let number of

atoms of Ni +2 =

CBSE CLASS 12TH ENGLISH CORE QUESTION PAPER SOLVED LAST 10 Question 6: (Marks 10) Rising prices of essential commodities make life difficult for the common man. You are Nalini / Ranbir. Write an article in 150-200 words describing the causes, possible solutions and how students can help their parents to cope with the problem. OR. QUESTION 5. YOU ARE GIVEN A HAMMER, A BATTERY, A BULB Answer: (a) If the substance can be hammered to convert into sheets then it is metal if it is broken into pieces then it is non-metal. Set up the arrangement using bulb, battery, wire and switch as shown in figure. Place the substance between Point A and B if the bulb starts glowing then the substance is a Metal otherwise it is non-metal GOLD (ATOMIC RADIUS = 0.144 NM) CRYSTALLISES IN A FACE Given that. Radius of atom R= 0.144 nm. For a face–centered unit cell. Edge a = 2√2 R. Plug the values we get. Edge a= 0.144 x 2 x 1,414 nm. Edge a= 0.407 nm. Solution:– The length of a side of the cell = 0.407 nm. Please send your queries to ncerthelp@gmail.com GIVEN THE STANDARD ELECTRODE POTENTIALS, K+/K = ?2.93V Question 2:Given the standard electrode potentials, K + /K = −2.93V, Ag + /Ag = 0.80V, Hg 2+ /Hg = 0.79V Mg 2+ /Mg = −2.37 V, Cr 3+ /Cr = − 0.74V Arrange these metals in their increasing order of reducing power. Answer:Reducing power of metals increase with decrease of reduction potential.Hence the increasing order of reducing power will Ag < Hg < Cr < Mg < K A GROUP 14 ELEMENT IS TO BE CONVERTED INTO N?TYPE Question 1.23: A group 14 element is to be converted into n−type semiconductor by doping it with a suitable impurity. To which group should this impurity belong? NOTES FOR CLASS 11 ALL SUBJECTS Chemistry Notes for Class 11 Download in pdf. Maths notes and formulas for class 11 download in pdf. Informatics Practices (IP) Notes for class 11 Download in Pdf. Physics notes class 11 cbse board download in pdf. Biology notes class 11 cbse board download in pdf. Economics Notes for class 11 Download in Pdf. Please send your queries at ACCOUNTANCY SAMPLE PAPER FOR CLASS 12 WITH SOLUTION NCERT Question 11: (Marks 1) Tangible Assets of the firm are ₹ 14,00,000 and outside liabilities are ₹ 4,00,000. Profit of the firm is ₹ 1,50,000 and normal rate of return is 10%. The amount of Capital employed will be. (a) ₹ 10,00,000. (b) ₹ 1,00,000. (c) ₹ 50,000. CBSE CLASS 12 PREVIOUS YEAR QUESTION PAPERS WITH SOLUTIONS Question 1: (Marks 1) Srishti, Nitya and Anand were partners in a firm sharing profits and losses in the ratio of 3 : 2 : 1. Srishti retired from the firm selling her share of profits to Nitya and Anand in the ratio of 2 : 1. The new profit sharing ratio between Nitya and Anand will be : (A) 3 : 2. (B) 17 : 11. DOWNLOAD PHYSICS NOTES FOR CLASS 12 CBSE BOARD ALL FORMULAS Chapter 12. ATOMS Download PDF. Chapter 13. Nulei Download PDF. Chapter 14. SEMICONDUCTOR ELECTRONICS: MATERIALS, DEVICES AND SIMPLE CIRCUITS. Chapter 15 & 8. COMMUNICATION SYSTEMS. Please send your queries to ncerthelp@gmail.com you can ECONOMICS SAMPLE PAPER FOR CLASS 12 WITH SOLUTION NCERT This statement is refuted because-. (i) Population growth has resulted in a very low growth in per capita income. (ii) The Green Revolution has increased the regional disparity and also the gap between the rich and the poor farmers. (iii) The gains of economic growth have been grabbed by the rich. OR. CBSE CLASS 12 BOARD EXAM ECONOMICS PAPER 2018 2019 2020 CBSE Class 12 Board Exam Economics Paper 2018 2019 2020 With Solutions. Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Class 12 Board Exam Economics Paper 2018 2019 2020 with Solutions Economics sample paper class 12, Economics previous year question paper class 12, cbse class 12

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QUESTION 3. ON COMPARING THE RATIOS A1/A2 , B1/B2 AND C1 Question 3. On comparing the ratios a1/a2 , b1/b2 and c1/c2 find. ☞ Class 12 Solved Question paper 2020. ☞ Class 10 Solved Question paper 2020. Question 3. On comparing the ratios a1/a2 , b1/b2 and c1/c2 find out whether the following pair of linear equations are consistent, or inconsistent. (i) 3x + CHEMISTRY FOR CLASS 11 PREVIOUS YEAR QUESTION PAPERS FOR CLASS 11 DOWNLOAD IN PDF. Last Year Question Paper of Chemistry for Class 11th 2015. Chemistry Last Yaer Question Paper For Cass 11th 2014. Chemistry Previous Yaer Question Paper for Class 11th 2013. Previous Year Question Paper of CBSE Exam of Chemistry For Class 11th 2012.pdf. Previous Year Question Paper of Chemistry For Class 11th

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GIVEN THE STANDARD ELECTRODE POTENTIALS, K+/K = ?2.93V Question 2:Given the standard electrode potentials, K + /K = −2.93V, Ag + /Ag = 0.80V, Hg 2+ /Hg = 0.79V Mg 2+ /Mg = −2.37 V, Cr 3+ /Cr = − 0.74V Arrange these metals in their increasing order of reducing power. Answer:Reducing power of metals increase with decrease of reduction potential.Hence the increasing order of reducing power will Ag < Hg < Cr < Mg < K SUGGEST A WAY TO DETERMINE THE ??M VALUE OF WATER. Question 3.8:Suggest a way to determine the Λ°m value of water. Answer: According to Kohlrausch’s law. Λ°m (H2O) = Λ°m (HCl) + Λ°m (NaOH) – Λ°m (NaCl) Hence if we know the values of Λ°m for HCl, NaOH, and NaCl, then we can calculate the value of Λ°m for the water. Please send your queries to ncerthelp@gmail.com you can aslo NCERT SOLUTIONS BOOKS CBSE MODEL TEST PAPERS QUESTION PDFCLASS 11 NOTES CHEMISTRY PHYSICS MATHEMATICSNCERT SOLUTIONSNCERT QUESTION PAPERSNCERT QUESTIONS FOR CLASS 7 Some of the Model test papers are published by NCERT Board. These model test papers contains 10th class maths model paper, maths model for class 9, cbse model paper class 9 ,class 9 science model paper, 10th model question paper etc. Class 1 Model Test Papers Download in pdf. Class 5 Model Test Papers Download in pdf. ANALYSIS SHOWS THAT NICKEL OXIDE HAS THE FORMULA NI0.98O1 Question 16 Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions? Answer Formula is Ni 0.98 O 1.00. So the ration of Ni : O = 98:100. So if there are 100 atoms of oxygen then 98 atoms of Ni. Let number of

atoms of Ni +2 =

CBSE PREVIOUS YEAR QUESTION PAPERS CLASS 12 ENGLISH CORE Question 1.1: (Marks 5) On the basis of your understanding of the above passage, answer any five of the following questions by choosing the most appropriate options : (a) The first green corridor in India was created in. (i) New Delhi. (ii) Chennai. QUESTION 3. ON COMPARING THE RATIOS A1/A2 , B1/B2 AND C1 Question 3. On comparing the ratios a1/a2 , b1/b2 and c1/c2 find. ☞ Class 12 Solved Question paper 2020. ☞ Class 10 Solved Question paper 2020. Question 3. On comparing the ratios a1/a2 , b1/b2 and c1/c2 find out whether the following pair of linear equations are consistent, or inconsistent. (i) 3x + CHEMISTRY NOTES FOR CLASS 12 CHAPTER 2 SOLUTIONS 5 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) (ix) Mass fraction Mass fraction of any component in the solution is the mass of that component divided by the total mass of the solution. CLASSIFY THE FOLLOWING SOLIDS IN DIFFERENT CATEGORIES Classify the following solids in different categories based on the nature of intermolecular forces operating in them: Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide. CHEMISTRY NOTES FOR CLASS 12 CHAPTER 1 THE SOLID STATE 2 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) Structure Determination by X-ray Diffraction (Bragg’s Equation) When a beam of X-rays falls on a crystal plane composed of regularly arranged atoms or ions, CHEMISTRY NOTES FOR CLASS 12 CHAPTER 3 ELECTROCHEMISTRY 1 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) Chemistry Notes for

class 12 Chapter 3

CALCULATE THE STANDARD CELL POTENTIALS OF GALVANIC CELLSGALVANIC CELL EXAMPLEGALVANIC CELL EXPERIMENTGALVANIC CELL SETUPGALVANIC CELL VOLTAGEGALVANIC CELL VS ELECTROLYTIC CELLHOW A GALVANIC CELL WORKS Question 4:Calculate the standard cell potentials of galvanic cells in which the following reactions take place: (i) 2Cr(s) + 3Cd 2+ (aq) → 2Cr 3+ (aq) + 3Cd (ii) Fe 2+ (aq) + Ag + (aq) → Fe 3+ (aq) + Ag(s) Calculate the =∆rG θ and equilibrium constant of the reactions.. Answer:(i) The galvanic cell of the given reaction is represented as SUGGEST A WAY TO DETERMINE THE ??M VALUE OF WATER. Question 3.8:Suggest a way to determine the Λ°m value of water. Answer: According to Kohlrausch’s law. Λ°m (H2O) = Λ°m (HCl) + Λ°m (NaOH) – Λ°m (NaCl) Hence if we know the values of Λ°m for HCl, NaOH, and NaCl, then we can calculate the value of Λ°m for the water. Please send your queries to ncerthelp@gmail.com you can aslo NCERT SOLUTIONS BOOKS CBSE MODEL TEST PAPERS QUESTION PDFCLASS 11 NOTES CHEMISTRY PHYSICS MATHEMATICSNCERT SOLUTIONSNCERT QUESTION PAPERSNCERT QUESTIONS FOR CLASS 7 Some of the Model test papers are published by NCERT Board. These model test papers contains 10th class maths model paper, maths model for class 9, cbse model paper class 9 ,class 9 science model paper, 10th model question paper etc. Class 1 Model Test Papers Download in pdf. Class 5 Model Test Papers Download in pdf. ANALYSIS SHOWS THAT NICKEL OXIDE HAS THE FORMULA NI0.98O1 Question 16 Analysis shows that nickel oxide has the formula Ni0.98O1.00. What fractions of nickel exist as Ni2+ and Ni3+ ions? Answer Formula is Ni 0.98 O 1.00. So the ration of Ni : O = 98:100. So if there are 100 atoms of oxygen then 98 atoms of Ni. Let number of

atoms of Ni +2 =

CBSE PREVIOUS YEAR QUESTION PAPERS CLASS 12 ENGLISH CORE Question 1.1: (Marks 5) On the basis of your understanding of the above passage, answer any five of the following questions by choosing the most appropriate options : (a) The first green corridor in India was created in. (i) New Delhi. (ii) Chennai. QUESTION 3. ON COMPARING THE RATIOS A1/A2 , B1/B2 AND C1 Question 3. On comparing the ratios a1/a2 , b1/b2 and c1/c2 find. ☞ Class 12 Solved Question paper 2020. ☞ Class 10 Solved Question paper 2020. Question 3. On comparing the ratios a1/a2 , b1/b2 and c1/c2 find out whether the following pair of linear equations are consistent, or inconsistent. (i) 3x + CHEMISTRY NOTES FOR CLASS 12 CHAPTER 2 SOLUTIONS 5 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) (ix) Mass fraction Mass fraction of any component in the solution is the mass of that component divided by the total mass of the solution. CLASSIFY THE FOLLOWING SOLIDS IN DIFFERENT CATEGORIES Classify the following solids in different categories based on the nature of intermolecular forces operating in them: Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide. CHEMISTRY NOTES FOR CLASS 12 CHAPTER 1 THE SOLID STATE 2 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) Structure Determination by X-ray Diffraction (Bragg’s Equation) When a beam of X-rays falls on a crystal plane composed of regularly arranged atoms or ions, CHEMISTRY NOTES FOR CLASS 12 CHAPTER 3 ELECTROCHEMISTRY 1 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) Chemistry Notes for

class 12 Chapter 3

CALCULATE THE STANDARD CELL POTENTIALS OF GALVANIC CELLSGALVANIC CELL EXAMPLEGALVANIC CELL EXPERIMENTGALVANIC CELL SETUPGALVANIC CELL VOLTAGEGALVANIC CELL VS ELECTROLYTIC CELLHOW A GALVANIC CELL WORKS Question 4:Calculate the standard cell potentials of galvanic cells in which the following reactions take place: (i) 2Cr(s) + 3Cd 2+ (aq) → 2Cr 3+ (aq) + 3Cd (ii) Fe 2+ (aq) + Ag + (aq) → Fe 3+ (aq) + Ag(s) Calculate the =∆rG θ and equilibrium constant of the reactions.. Answer:(i) The galvanic cell of the given reaction is represented as SUGGEST A WAY TO DETERMINE THE ??M VALUE OF WATER. Question 3.8:Suggest a way to determine the Λ°m value of water. Answer: According to Kohlrausch’s law. Λ°m (H2O) = Λ°m (HCl) + Λ°m (NaOH) – Λ°m (NaCl) Hence if we know the values of Λ°m for HCl, NaOH, and NaCl, then we can calculate the value of Λ°m for the water. Please send your queries to ncerthelp@gmail.com you can aslo CBSE CLASS 12 PREVIOUS YEAR QUESTION PAPERS WITH SOLUTIONS Question 1: (Marks 1) Srishti, Nitya and Anand were partners in a firm sharing profits and losses in the ratio of 3 : 2 : 1. Srishti retired from the firm selling her share of profits to Nitya and Anand in the ratio of 2 : 1. The new profit sharing ratio between Nitya and Anand will be : (A) 3 : 2. (B) 17 : 11. CBSE CLASS 12 BOARD EXAM ACCOUNTANCY PAPER 2018 2019 2020 Question 4: (Marks 1) Diya, Riya and Tiya were partners sharing profits and losses in the ratio of 2 : 3 : 5. Tiya died on 28 th November, 2019. Her share of profit was taken equally by Diya and Riya. Diya’s share of profit in the new firm will be _________ .

Answer :

CALCULATE THE STANDARD CELL POTENTIALS OF GALVANIC CELLS Question 4:Calculate the standard cell potentials of galvanic cells in which the following reactions take place: (i) 2Cr(s) + 3Cd 2+ (aq) → 2Cr 3+ (aq) + 3Cd (ii) Fe 2+ (aq) + Ag + (aq) → Fe 3+ (aq) + Ag(s) Calculate the =∆rG θ and equilibrium constant of the reactions.. Answer:(i) The galvanic cell of the given reaction is represented as CBSE PREVIOUS YEAR QUESTION PAPERS CLASS 12 BIOLOGY WITH Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Previous Year Question Papers Class 12 Biology with Solutions Biology sample paper class 12, Biology previous year question paper class 12, cbse class 12 Biology sample paper, cbse class 12 Biology sample paper 2020, Biology sample paper class 12 2020, cbse sample paper 2020 class 12 Biology, class CBSE CLASS 12 BOARD EXAM ECONOMICS PAPER 2018 2019 2020 CBSE Class 12 Board Exam Economics Paper 2018 2019 2020 With Solutions. Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Class 12 Board Exam Economics Paper 2018 2019 2020 with Solutions Economics sample paper class 12, Economics previous year question paper class 12, cbse class 12

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GIVEN THE STANDARD ELECTRODE POTENTIALS, K+/K = ?2.93V Question 2:Given the standard electrode potentials, K + /K = −2.93V, Ag + /Ag = 0.80V, Hg 2+ /Hg = 0.79V Mg 2+ /Mg = −2.37 V, Cr 3+ /Cr = − 0.74V Arrange these metals in their increasing order of reducing power. Answer:Reducing power of metals increase with decrease of reduction potential.Hence the increasing order of reducing power will Ag < Hg < Cr < Mg < K BIOLOGY NOTES FOR CLASS 12 CBSE BOARD DOWNLOAD PDF biology notes for class 12 download in pdf. chapter 1. reproduction in organisms chapter 2. sexual reproduction in flowering plants GOLD (ATOMIC RADIUS = 0.144 NM) CRYSTALLISES IN A FACE Given that. Radius of atom R= 0.144 nm. For a face–centered unit cell. Edge a = 2√2 R. Plug the values we get. Edge a= 0.144 x 2 x 1,414 nm. Edge a= 0.407 nm. Solution:– The length of a side of the cell = 0.407 nm. Please send your queries to ncerthelp@gmail.com CHEMISTRY NOTES FOR CLASS 12 CHAPTER 15 POLYMERS 2 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) (iii) Semisynthetic polymers Polymers obtained by making some modification in natural polymers by artificial means, are known as semi synthetic polymers, e.g., cellulose acetate QUESTION 2 YOU KNOW THAT 1/7 = 0.142857 BAR . CAN YOU Question 2 You know that 1/7 = 0.142857 bar . Can you predict what the decimal expansion of 2/7 , 3/7 ,4/7 , 5/7 and 6/ 7 are, without actually doing the long division? If so, how? Solution: Please send your queries to ncerthelp@gmail.com you can aslo visit our

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NCERT SOLUTIONS BOOKS CBSE MODEL TEST PAPERS QUESTION PDFCLASS 11 NOTES CHEMISTRY PHYSICS MATHEMATICSNCERT SOLUTIONSNCERT QUESTION PAPERSNCERT QUESTIONS FOR CLASS 7 Ncert Solution for class 6 to 12 download in pdf . Ncert Help provides best ncert solution for class 1,2,3,4,5,6,7,8,9,10,11,12. Student can also download these solutions in pdf. ANALYSIS SHOWS THAT NICKEL OXIDE HAS THE FORMULA NI0.98O1 Question 16 Analysis shows that nickel oxide has the formula Ni 0.98 O 1.00.What fractions of nickel exist as Ni 2+ and Ni 3+ ions?. AnswerFormula is Ni 0.98 O 1.00 So the ration of Ni : O = 98:100 So if there are 100 atoms of oxygen then 98 atoms of Ni CBSE PREVIOUS YEAR QUESTION PAPERS CLASS 12 ENGLISH CORE Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Previous Year Question Papers Class 12 English Core with Solutions English Core sample paper class 12, English Core previous year question paper class 12, cbse class 12 English Core sample paper, cbse class 12 English Core sample paper 2020, English Core sample paper class 12 2020, cbse sample CHEMISTRY NOTES FOR CLASS 12 CHAPTER 2 SOLUTIONS 5 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) (ix) Mass fraction Mass fraction of any component in the solution is the mass of that component divided by the total mass of the solution. CLASSIFY THE FOLLOWING SOLIDS IN DIFFERENT CATEGORIES Classify the following solids in different categories based on the nature of intermolecular forces operating in them: Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide. CHEMISTRY NOTES FOR CLASS 12 CHAPTER 3 ELECTROCHEMISTRY 1 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) Chemistry Notes for

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QUESTION 3. ON COMPARING THE RATIOS A1/A2 , B1/B2 AND C1 Question 3. On comparing the ratios a1/a2 , b1/b2 and c1/c2 find out whether the following pair of linear equations are consistent, or

inconsistent.

CALCULATE THE STANDARD CELL POTENTIALS OF GALVANIC CELLSGALVANIC CELL EXAMPLEGALVANIC CELL EXPERIMENTGALVANIC CELL SETUPGALVANIC CELL VOLTAGEGALVANIC CELL VS ELECTROLYTIC CELLHOW A GALVANIC CELL WORKS Question 4:Calculate the standard cell potentials of galvanic cells in which the following reactions take place: (i) 2Cr(s) + 3Cd 2+ (aq) → 2Cr 3+ (aq) + 3Cd (ii) Fe 2+ (aq) + Ag + (aq) → Fe 3+ (aq) + Ag(s) Calculate the =∆rG θ and equilibrium constant of the reactions.. Answer:(i) The galvanic cell of the given reaction is represented as GIVEN THE STANDARD ELECTRODE POTENTIALS, K+/K = ?2.93V Question 2:Given the standard electrode potentials, K + /K = −2.93V, Ag + /Ag = 0.80V, Hg 2+ /Hg = 0.79V Mg 2+ /Mg = −2.37 V, Cr 3+ /Cr = − 0.74V Arrange these metals in their increasing order of reducing power. Answer:Reducing power of metals increase with decrease of reduction potential.Hence the increasing order of reducing power will Ag < Hg < Cr < Mg < K SUGGEST A WAY TO DETERMINE THE ??M VALUE OF WATER. Question 3.8:Suggest a way to determine the Λ°m value of water. Answer:According to Kohlrausch’s law Λ°m(H2O) = Λ°m(HCl) + Λ°m(NaOH) – Λ°m(NaCl) Hence if we know the values of Λ°m for HCl, NaOH, and NaCl, then we can calculate the value of Λ°m for the

water

NCERT SOLUTIONS BOOKS CBSE MODEL TEST PAPERS QUESTION PDFCLASS 11 NOTES CHEMISTRY PHYSICS MATHEMATICSNCERT SOLUTIONSNCERT QUESTION PAPERSNCERT QUESTIONS FOR CLASS 7 Ncert Solution for class 6 to 12 download in pdf . Ncert Help provides best ncert solution for class 1,2,3,4,5,6,7,8,9,10,11,12. Student can also download these solutions in pdf. ANALYSIS SHOWS THAT NICKEL OXIDE HAS THE FORMULA NI0.98O1 Question 16 Analysis shows that nickel oxide has the formula Ni 0.98 O 1.00.What fractions of nickel exist as Ni 2+ and Ni 3+ ions?. AnswerFormula is Ni 0.98 O 1.00 So the ration of Ni : O = 98:100 So if there are 100 atoms of oxygen then 98 atoms of Ni CBSE PREVIOUS YEAR QUESTION PAPERS CLASS 12 ENGLISH CORE Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Previous Year Question Papers Class 12 English Core with Solutions English Core sample paper class 12, English Core previous year question paper class 12, cbse class 12 English Core sample paper, cbse class 12 English Core sample paper 2020, English Core sample paper class 12 2020, cbse sample CHEMISTRY NOTES FOR CLASS 12 CHAPTER 2 SOLUTIONS 5 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) (ix) Mass fraction Mass fraction of any component in the solution is the mass of that component divided by the total mass of the solution. CBSE PREVIOUS YEAR QUESTION PAPERS CLASS 12 BIOLOGY WITH Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Previous Year Question Papers Class 12 Biology with Solutions Biology sample paper class 12, Biology previous year question paper class 12, cbse class 12 Biology sample paper, cbse class 12 Biology sample paper 2020, Biology sample paper class 12 2020, cbse sample paper 2020 class 12 Biology, class CBSE PREVIOUS YEAR QUESTION PAPERS CLASS 12 ACCOUNTANCY Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Previous Year Question Papers Class 12 Accountancy with Solutions Accountancy sample paper class 12, Accountancy previous year question paper class 12, cbse class 12 Accountancy sample paper, cbse class 12 Accountancy sample paper 2020, Accountancy sample paper class 12 2020, cbse sample CBSE CLASS 12TH ENGLISH CORE QUESTION PAPER SOLVED LAST 10 Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Class 12th English Core Question Paper Solved Last 10 Years with Solution English Core sample paper class 12, English Core previous year question paper class 12, cbse class 12 English Core sample paper, cbse class 12 English Core sample paper 2020, English Core sample paper class 12 2020, cbse CBSE CLASS 12 BOARD EXAM ACCOUNTANCY PAPER 2018 2019 2020 Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Class 12 Board Exam Accountancy Paper 2018 2019 2020 with Solutions Accountancy sample paper class 12, Accountancy previous year question paper class 12, cbse class 12 Accountancy sample paper, cbse class 12 Accountancy sample paper 2020, Accountancy sample paper class 12 2020, cbse GIVEN THE STANDARD ELECTRODE POTENTIALS, K+/K = ?2.93V Question 2:Given the standard electrode potentials, K + /K = −2.93V, Ag + /Ag = 0.80V, Hg 2+ /Hg = 0.79V Mg 2+ /Mg = −2.37 V, Cr 3+ /Cr = − 0.74V Arrange these metals in their increasing order of reducing power. Answer:Reducing power of metals increase with decrease of reduction potential.Hence the increasing order of reducing power will Ag < Hg < Cr < Mg < K CBSE CLASS 12 BOARD EXAM ECONOMICS PAPER 2018 2019 2020 Here we are providing CBSE Previous Year Question Papers Class 6 to 12 solved with soutions CBSE Class 12 Board Exam Economics Paper 2018 2019 2020 with Solutions Economics sample paper class 12, Economics previous year question paper class 12, cbse class 12 Economics sample paper, cbse class 12 Economics sample paper 2020, Economics sample paper class 12 2020, cbse sample paper 2020 BIOLOGY NOTES FOR CLASS 12 CBSE BOARD DOWNLOAD PDF biology notes for class 12 download in pdf. chapter 1. reproduction in organisms chapter 2. sexual reproduction in flowering plants CHEMISTRY NOTES FOR CLASS 12 CHAPTER 15 POLYMERS 2 | P a g e www.ncerthelp.com (Visit for all ncert solutions in text and videos, CBSE syllabus, note and many more) (iii) Semisynthetic polymers Polymers obtained by making some modification in natural polymers by artificial means, are known as semi synthetic polymers, e.g., cellulose acetate GOLD (ATOMIC RADIUS = 0.144 NM) CRYSTALLISES IN A FACE Gold (atomic radius = 0.144 nm) crystallises in a face–centred unit cell. What is the length of a side of the cell QUESTION 2 YOU KNOW THAT 1/7 = 0.142857 BAR . CAN YOU Question 2 You know that 1/7 = 0.142857 bar . Can you predict what the decimal expansion of 2/7 , 3/7 ,4/7 , 5/7 and 6/ 7 are, without actually doing the long division? Home UP BOARD Question Papers

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