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EVERYBODY DURING THE LAST LESSON IS FILLED WITH REGRETFILLED WITH REGRET CROSSWORDFILLED WITH REGRETIT IS WITH MUCH REGRETHOW TO LIVE WITH REGRETSWORD OF REGRET3 LETTER WORD FOR REGRET According to the order from Berlin, only German was to be taught in the schools of Alsace and Lorraine. This order left Mr. Hamel, the village people and the Mr. Hamel s students in deep regret. The villagers regretted not having made utmost use of the French lessons that they had been given by Mr Hamel. They had engaged themselves in their profession to earn a living and had not taken their AN ELECTRIC DIPOLE OF LENGTH 4 CM, WHEN PLACED WITH ITS An electric dipole of length 4 cm, when placed with its axis making an angle of 60° with a uniform electric field experiences a torque of 4 3 Nm. Calculate the (i) magnitude of the electric field. (ii) potential energy of the dipole, if the dipole has charges of ± 8nC. CRITICALLY APPRAISE SOME OF THE SHORTFALLS OF THE Following were some of the short falls of industrial policy pursued by the British colonial administration: 1. De-industrialisation : India could not develop a sound industrial base under the colonial rule. Even the country s world famous handicraft industries declined. No corresponding modern industrial base was allowed to come up to take pride place so long enjoyed by the former. CALCULATE THE WORK DONE TO DISSOCIATE THE SYSTEM OF THE Given charge q = 8 mC = 8 x 10 –1 C is located at origin and the small charge (q 0 = –2 x 10 –9 C) is taken from point P (0, 0, 3 cm) to a point Q (0, 4, cm, 0) through point R (0, 6 cm, 9 cm) which is shown in the figure. Initial separation between q 0 and q is r p = 3 cm = 0.03 m Final separation between q 0 and q is r Q = 4 cm = 0.4 m Work done in taking the charge q 0 from point P to AN A.C. SUPPLY OF 230 V IS APPLIED TO A HALF-WAVE An a.c. supply of 230 V is applied to a half-wave rectifier circuit through a transformer of turn ratio 10: 1. Find the output d.c. voltage. Assume the diode to be ideal. A CHARGE OF 8 MC IS LOCATED AT THE ORIGIN. CALCULATE THE Given charge q = 8 mC = 8 x 10–1 C is located at origin and the small charge (q0 = –2 x 10–9 C) is taken from point P (0, 0, 3 cm) to a point Q (0, 4, cm, 0) through point R (0, 6 cm, 9 cm) which is shown in the figure.Initial separation between q0 and q is rp = 3 cm = 0.03 mFinal separation between q0 and q is rQ = 4 cm = 0.4 mWork done in taking the charge q0 from point P to Q does not THE VECTORS OF MAGNITUDE A, 2A, 3A MEET AT A POINT AND Let be unit vectors along OA, OC, OE respectively. Let OB, OD, OF be the diagonals of faces OABC, OCDE, OEFA respectively of the cube of side of length b. Now unit vector along Similarly unit vector along = and unit vector along Let be resultant of vectors magnitude ofresultant vector =
EVERYBODY DURING THE LAST LESSON IS FILLED WITH REGRETFILLED WITH REGRET CROSSWORDFILLED WITH REGRETIT IS WITH MUCH REGRETHOW TO LIVE WITH REGRETSWORD OF REGRET3 LETTER WORD FOR REGRET According to the order from Berlin, only German was to be taught in the schools of Alsace and Lorraine. This order left Mr. Hamel, the village people and the Mr. Hamel s students in deep regret. The villagers regretted not having made utmost use of the French lessons that they had been given by Mr Hamel. They had engaged themselves in their profession to earn a living and had not taken their AN ELECTRIC DIPOLE OF LENGTH 4 CM, WHEN PLACED WITH ITS An electric dipole of length 4 cm, when placed with its axis making an angle of 60° with a uniform electric field experiences a torque of 4 3 Nm. Calculate the (i) magnitude of the electric field. (ii) potential energy of the dipole, if the dipole has charges of ± 8nC. A CHARGE OF 8 MC IS LOCATED AT THE ORIGIN. CALCULATE THE Given charge q = 8 mC = 8 x 10–1 C is located at origin and the small charge (q0 = –2 x 10–9 C) is taken from point P (0, 0, 3 cm) to a point Q (0, 4, cm, 0) through point R (0, 6 cm, 9 cm) which is shown in the figure.Initial separation between q0 and q is rp = 3 cm = 0.03 mFinal separation between q0 and q is rQ = 4 cm = 0.4 mWork done in taking the charge q0 from point P to Q does not AN ELECTRIC DIPOLE OF LENGTH 4 CM, WHEN PLACED WITH ITS An electric dipole of length 4 cm, when placed with its axis making an angle of 60° with a uniform electric field experiences a torque of 4 3 Nm. Calculate the (i) magnitude of the electric field. (ii) potential energy of the dipole, if the dipole has charges of ± 8nC. A PARTICLE MOVES IN A CIRCLE WITH O AS CENTRE AND AO = OB A driver of a car travelling at 52 km h –1 applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. Another driver going at 34 km h –1 in another car applies his brakes slowly and stops in 10 s. On the same graph paper, plot the speed versus time graphs for the two cars. SOLVE THE FOLLOWING PAIR OF LINEAR EQUATIONS:152X 152x - 378y = -74-378x + 152y = -604The given pair of linear equations is152x - 378y = -74 (i)-378x + 152y = -604 (ii)Adding equation (i) and equation (ii), we get-226x - 226y = -678⇒ x + y = 3 (iii)Subtracting equation (ii) from equation (i), we get530x - 530y = 530⇒ x - y = 1 (iv)Adding equation (iii) and equation (iv GIVE A CHARACTER-SKETCH OF THE GOVERNOR OF OXFORD PRISON The Governor of the HM Prison, Oxford appears to be a considerate and kind-hearted fellow at the start as he arranges for an O-level language exam for a prisoner notorious for his ability to escape from the prison. However, he is quite skeptical of Evans and makes every arrangement to make sure that Evans doesn t escape. He is also rather proud and self-conscious from his prison. AN ELECTRIC IRON CONSUMES ENERGY AT A RATE OF 840 W WHEN Given, Voltage of the mains supply, V = 220 VPower is given by, P = VICase 1: When heating is at maximum rate, Power, P = 840 W Potential difference, V = 220 V Current, I = PV = 840 W220 V = 3.82 A.∴ Resistance of the electric iron, R = VI = 220 V3.82 A = 57.60 Ω. Case 2: When heating is at the minimum rate, Power, P = 360 WPotential differnce, V = 220 V Current, I=PV = 360 W220 V = 1.64 A A SOLUTION PREPARED BY DISSOLVING 8.95 MG OF A GENE The molar concentration of the gene fragment Here, WB = 8.95 mg = 8.95 x 10-3 g, R = 0.0821 L atm Mol-1 K-1 T = 250C = (25 + 273) K = 298 K. = 0.355torr =0.355/760 atm V = 35 mL = 35 x 10-3 L Substituting these values in the above equation, we get WHAT IMPRESSION DO YOU FORM OF JACK AS A FATHER? (SHOULD Jack is a very smart father who has an inventive mind of creating stories. The basic line was the same but there was a little variation. Each story described a creature named Roger. He had to manage his family as two children, a daughter Jo and her brother Bobby. The world up stairs in the house consists of his children Jo and Jack. The downside world consists of his wife Clase who is doing HOW DID DR. SADAO RISE ABOVE NARROW PREJUDICES OF RACE AND Dr. Sadao Holu was a very dutiful and an humanitanan doctor. He was very much compeled by his duty to help the enemy solder. Instead of caring for the prejudices of race and country he rose above to save the American soldier. His wife too lent a helping hand without paying any heed whether the patient was an enemy or a friend. He was floating his duties as a doctor and the enemy on the other A POINT CHARGE CAUSES AN ELECTRIC FLUX OF -1.0 X 103 NM2/C Given, Φ = –1.0 x 103 Nm2/Cr1 = 0.1 m, r2 = 0.2 m(a) Doubling the radius of Gaussian surface will not affect the electric flux since the charge enclosed is the same in the two cases. Thus, the flux will remain be the same i.e., –1.0 x 103 Nm2/C(b)Join In
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